Sample 4 --- a non-series/parallel system

In this sample, we have a non-series/parallel system with 6 modules and 5 nodes.

1. Input the configuration of the system

NodesNum = 5      ModulesNum = 6
InputNode = 1      OutputNode = 5

A = (1, 2)
B = (1, 3)
C = (2, 3)
D = (2, 4)
E = (3, 4)
F = (4, 5)

2. Click the first RUN, then you will get below:
Result:

The diagram is shown below:

```

```
`System Reliability = `
```     - Ra*Rb*Rc*Re*Rf
+ Ra*Rb*Rc*Rd*Re*Rf
+ Ra*Rd*Rf
+ Rb*Re*Rf
- Ra*Rb*Rd*Re*Rf
+ Ra*Rc*Re*Rf
- Ra*Rc*Rd*Re*Rf```
3. Input the numeric value of reliability for each module:
0.9, 0.8, 0.7, 0.5, 0.9, 0.9
Click the second RUN, then you will get below:
Result:

The diagram is shown below

` `
```System Reliability =

- Ra*Rb*Rc*Re*Rf
+ Ra*Rb*Rc*Rd*Re*Rf
+ Ra*Rd*Rf
+ Rb*Re*Rf
- Ra*Rb*Rd*Re*Rf
+ Ra*Rc*Re*Rf
- Ra*Rc*Rd*Re*Rf```
```
Given Ra=0.9, Rb=0.8, Rc=0.7, Rd=0.5, Re=0.9, Rf=0.9,
Rsystem = 0.8124300000000002```

4. Input the numeric value of failure rate for each module:
1.5, 2, 2.5, 3, 3.5, 4
Click the third RUN, then you will get below:
Result:

The diagram is shown below:

```

```

System Reliability =

- e-1.5t*e-2t*e-2.5t*e-3.5t*e-4t
+ e-1.5t*e-2t*e-2.5t*e-3t*e-3.5t*e-4t
+ e-1.5t*e-3t*e-4t
+ e-2t*e-3.5t*e-4t
- e-1.5t*e-2t*e-3t*e-3.5t*e-4t
+ e-1.5t*e-2.5t*e-3.5t*e-4t
- e-1.5t*e-2.5t*e-3t*e-3.5t*e-4t

The diagram of R(t) vs time t is shown below:
```

x10-1sec
```

R(t) = 0.8 when t = 0.0457763671875
R(t) = 0.5 when t = 0.1220703125
R(t) = 0.3 when t = 0.194549560546875
R(t) = 0.1 when t = 0.331878662109375

At time t = .1, R(t) = 0.5824351207217396

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