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Sample 3 --- a series/parallel system

In this sample, we have a complex series/parallel system with 8 modules and 7 nodes.

1. Input the configuration of the system

NodesNum = 7 ModulesNum = 8
InputNode = 1 OutputNode = 5

A = (1, 2)

B = (2, 3)

C = (3, 4)

D = (3, 4)

E = (1, 6)

F = (6, 7)

G = (7, 4)

H = (4, 5)

2. Click the first RUN, then you will get below:

Result:

The diagram is shown below:

System Reliability = (1-(1-R_a*R_b*(1-(1-R_c)*(1-R_d)))*(1-R_e*R_f*R_g))*R_h

3. Input the numeric value of reliability for each module:

0.9, 0.8, 0.7, 0.8, 0.9, 0.5, 0.6, 0.9
Click the second RUN, then you will get below:
Result:
The diagram is shown below:
System Reliability = (1-(1-R_a*R_b*(1-(1-R_c)*(1-R_d)))*(1-R_e*R_f*R_g))*R_h
Given R_a= 0.9, R_b = 0.8, R_c= 0.7, R_d = 0.8, R_e= 0.9, R_f = 0.5, R_g= 0.6, R_h = 0.9,
R_system= 0.6876576000000001

4. Input the numeric value of failure rate for each module:

1.5, 2, 2.5, 3, 3.5, 4, 4.5, 5
Click the third RUN, then you will get below:
Result:
The diagram is shown below:
System Reliability = (1-(1-e^-1.5t*e^-2t*(1-(1-e^-2.5t)*(1-e^-3t)))*(1-e^-3.5t*e^-4t*e^-4.5t))*e^-5t
^{The diagram of R(t) vs time t is shown below:}
x10^-2sec
At time t = .1, R(t) =.46423998546424144

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