
ECE
585 Home
Announcements
Course
Objectives
Lecture
Schedule
Homework
Assignments and Solutions
Homework
Help
Book
References
Software
References
Other
RF Links
microwaves101.com


Homework Help and
Worked Problem Examples
Solutions to the HWs
will be posted about a week after they are due. In the meantime, I am
posting answers to some of the problems for the first few problem sets.
This will help you know if you're on the right track. Last updated: January
15, 2005.
HW
Set 
Problem 
Answer,
comments 
1 
7.2 
RL
= 26 dB, C = 20 dB, D = 6 dB, I = 26 dB 

7.6 
Check
your formulas for the Tee network with these specific cases: for Zo
= 50 ohms, if alpha = 3 dB (.708), then R1 = 8.6 ohms, R2 = 141.9
ohms 

7.7 
Design:
Zo = 100 ohms, R = 33.3 ohms; ratio of P3(mismatched) to P3 (matched)
= 1.326 (1.2 dB) 
2 
7.9 
Zo3
= 131.7 ohms, Zo2 = 43.9 ohms, R = 115.5 ohms; output impedances are
R2 = 28.9 ohms, R3 = 86.7 ohms 

7.13 
Bethe
hole coupler; ro = 1.90 mm 

7.14 
5hole
coupler; ro = r4 = 1.87 mm; r1 = r3 = 2.97 mm; r2 = 3.42 mm 

7.15 
ro
= r4 = 2.19 mm; r1 = r3 = 2.93 mm; r2 = 2.54 mm 
3 
7.18 
S
= 0.24 mm; W = 2.1 mm 

7.19 
Zoe
= 61 ohms; Zoo = 35 ohms 

7.21 
S
= 1.15 mm; W = 1.92 mm; line lengths = 6.32 mm 

7.22 
S
= 0.029 mm (really thin!) ; W = 1.09 mm (not a practical
design...) 

7.29 
V1
= 0; V2 = (j / sqrt[2]) (V1  V4); V3 = (j / sqrt[2] ) (V1 + V4
); V4 = 0 

7.33 
Here's a helpful
hint on solving Prob. 7.33
for the Bailey power divider. 
5 
8.1 
Here
are two points from the graph: (1) when z = 0.75 lambda, voltage magnitude
= 18.8 V; (2) when z = 2.75 lambda, voltage magnitude = 6.25 V. 

8.13 
After
using Richards' transforms and first Kuroda identity, transform circuit
to one having three series stubs (25 ohms, 100 ohms, 25 ohms), and
two mainline sections in the middle, each with 25 ohms Zo 

8.17 
from
left, electrical lengths are 14.7deg, 35.2 deg, 21.8 deg, 35.2 deg,
14.7 deg; characteristic impedances are (from left) 15 ohms, 200 ohms,
15 ohms, 200 ohms, 15 ohms 




