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CEE 370 |
Fall 2010 |
How
many grams of anhydrous Sodium Sulfate (Na2SO4) must be
added to a liter of water so that the ionic strength equals 0.01M?![]()
for a solution of sodium sulfate at a molar concentration of “C”, we have “C” moles of sulfate (a divalent ion) and “2C” moles of sodium (a monovalent ion). Therefore,
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since the GFW of Na2SO4 is (2x23)+32+(4x16)=142
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The
pesticide, parathion, undergoes photolytic degradation (destruction by
absorption of energy from the sun’s rays) in natural waters. This is a first order process with a rate
constant of 8x10-7s-1.![]()
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Hypochlorous
acid (HOCl) reacts with phenol (C6H5OH) to produce a wide
range of products including highly offensive chlorophenols. The rate of this reaction is second order,
overall (first order in each reactant).
The rate constant is 2x103 M-1s-1. In this problem you have 1.2 ppb of phenol in
water, and to this you add 0.1 mM hypochlorous acid.First, calculate molar phenol concentration.
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Although this is a second order kinetic problem, one of the reactants (hypochlorous acid) is present at a very large molar excess (e.g., 0.1 mM vs 0.0000128mM). Therefore, this reactant will not become depleted as the reaction proceeds, and the overall reaction takes on the form of pseudo-first order kinetics.
So the following equation will hold:
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Where:
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and now we can simply used the re-arranged form of the first order kinetic equation as developed in question #2 above.
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And using the same equation again:
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Calculate the ThOD of the following wastewatersThe balanced stoichiometric equation is:
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The ThOD is then:

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The balanced stoichiometric equation is:
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The ThOD is then:

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The ThOD of the two components are calculated in parts a and b. The answer is the sum of the two, or:
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First, the mass-based concentration is:
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The balanced stoichiometric equation is:
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The ThOD is then:

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The balanced stoichiometric equation is:
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The ThOD is then:

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Nitrogen
occurs at a variety of oxidation states in water environments. Balance the
following oxidation-reduction reaction which is important in wastewater
treatment:NH3 + O2 → NO3- + H2O
Show all steps.
Oxidation: ![]()
Reduction: ![]()
Multiply the reduction reaction by 2x and adding the two we get:
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